Question

4

A particles projected at an angle 60 from vertical with a velocity 20 m/s in a vertical plane Find velocity
of projecctile afer 1s. ( = 10 m/s)
1) 55 m/s
(2) 2.2 m/s
) 23 m,/s
(4) 103 m/s​

Answer 1

Answer:

b) 2.2 m/s

I am not sure about the answer

Answer 2

Answer:

12.39 m/s

Explanation:

after 1s

vx = 20cos60 = 10

vy = 10(√3-1)

v² = vx² + vy² = 100(5-2√3)

v = 10√(5-2√3) = 12.39 m/s