Question

4. A plate load test was conducted in sand on a 300mm diameter plate. If the plate settlement was 5
mm at a pressure of 100 kpa, the settlement (in mm) of a 5 m x 8 m rectangular footing at the same
pressure will be​

Answer 1

Answer:

17.8

Explanation:

Answer 2

Answer:

The settlement of the rectangular footing is 17.8mm.

Explanation:

Given the diameter of plate, $B_P= 300mm =0,3m$

Plate settlement, $S_P= 5 mm$

Pressure, $\rho=100 kpa$

Width of the settlement,  $B=5 m$

Given the pressure is same in both the cases.

Then the settlement of foundation in sand is given by

$S=S_{P} \Bigg[\dfrac{B(B_{P} +0.3)}{B_{P} (B+0.3)} \Bigg]^{2}$

where B & $B_P$ are width of foundation and plate respectively,

and S & $S_P$ are settlement of foundation and plate respectively.

Substituting the given values,

$S=5 \Bigg[\dfrac{5(0.3 +0.3)}{0.3 (5+0.3)} \Bigg]^{2}$

$=5 \Bigg[\dfrac{5(0.6)}{0.3 (5.3)} \Bigg]^{2}=17.8mm$

Therefore, the settlement of the rectangular footing in sand is 17.8mm.