The polynomials ax3 3x2 + 4 and 2x3 5x + a when divided by ( x 2 ) leave the remainder p and q' respectively. If p 2 q = 4, find the value of a'
Answers
Answered by
5
x=2 a{2}3-3{2}2+4=8a-8 _p
2{2]3-5{2}+a =6+a _q
8a-8-2(6+a) =4
8a--8-12-2a=4
8a-20-2a=4
8a-2a=4+20
6a=24
a=24/6
a=4
Answered by
1
Answer:
x=2 a{2}3-3{2}2+4=8a-8 _p
2{2]3-5{2}+a =6+a _q
8a-8-2(6+a) =4
8a--8-12-2a=4
8a-20-2a=4
8a-2a=4+20
6a=24
a=24/6
a=4
Step-by-step explanation:
Similar questions