Physics, asked by mohitdeepsingh16, 8 months ago

4. A shot put player thrown a
shot-put of mass 3 kg. if it
crosses the top of wall of 2m
high at a speed of 4 m/s .
compute mechanical energy *
78.67J
64.21J
81.78J
O 82.85J​

Answers

Answered by SujalSirimilla
3

Answer:

\bigstar GIVEN:

  • Mass (m) = 3 Kg.
  • Height (h) = 2m.
  • Speed (v) = 4ms⁻¹.
  • Acceleration due to gravity (g) = 9.806ms⁻¹.

\bigstar SOLUTION:

M.E = K. E + P.E. \\M.E. =  \frac{1}{2} $ mv^2 + mgh

Where M.E. = Mechanical energy, P.E = Potential energy, K.E. = Kinetic energy.

Substitute the values.

M.E. =  \frac{1}{2} $ \times 3 \times 4^2  + 3 \times 2 \times 9.806

M.E. = 24 + 58.836

M.E. = 82.836J

M.E.=82.85J \: \: [Rounded \: \: off  \: \: to \: \: the \: \: nearest \: \: decimal]

OPTION D IS CORRECT.

{\huge{\mathfrak{\underbrace{\blue{HOPE \:\: THIS \:\: HELPS \:\: :D}}}

Similar questions