Question

4. A solution contains 20 mL methanol, 30 mL
ethanol and 50 mL of acetone. What is the volume
percentage of each constituent.
OY100
[Ans. 20%, 30%, and 50%​

Answer 1

Explanation:

Volume of methanol = 20 ml

Volume of ethanol= 30 ml

Volume of acetone = 50 ml

Total volume of the solution = (20+30+50)ml = 100 ml

-Volume percentage of methanol = 20/100*100 = 20 %

-Volume percentage of ethanol= 30/100*100 = 30%

-Volume percentage of acetone = 50/100*100 = 50 %