Question

4. A swimming pool is 15 m in length, 12 m in breadth and 2 m in depth. Find the cost of cementing the floor and walls at the rate of 15 per sq. m.​

Answer 1

Given :-

• Length of the pool = 15m
• Breadth of the pool = 12m
• Height of the pool = 2m
• Rate of Cementing = Rs, 15 per m

To Find :-

• Cost of Cementing the Floor and Walls.

Solution :-

★ Area of Floor ★

⇒ Area of Floor = Length × Breadth

⇒ Area of Floor = 15 × 12

⇒ Area of Floor = 180m²

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★ Area of Walls ★

⇒ Area of Walls = 2h ( l + b )

⇒ Area of Walls = 2 × 2 ( 15 + 12 )

⇒ Area of Walls = 4 × 27

⇒ Area of Walls = 108m²

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★ Total Area to be Cemented ★

⇒ Total Area = Area of floor + Area of Walls

⇒ Total Area = 180 + 108

⇒ Total Area = 288m²

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★ Cost of Cementing ★

⇒ Cost = Total Area × Rate of Cementing

⇒ Cost = 288 × 15

⇒ Cost of Cementing = Rs, 4320

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∴ Cost of Cementing the pool is Rs, 4320.

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Answer 2

Step-by-step explanation:

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$\huge{\underline{\red{\mathrm{Question}}}}$

A swimming pool is 15 m in length, 12 m in breadth and 2 m in depth. Find the cost of cementing the floor and walls at the rate of 15 per sq. m.

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$\huge{\underline{\mathrm{Given\: :-}}}$

∴$\sf\blue{⇒Length \:of \:pool \:(l)\:=15m }$

∴$\sf\blue{⇒Breadth\: of \:pool\: (b)\:=12m }$

∴$\sf\blue{⇒Height\: of \:pool \:(h)=2m }$

$\huge{\underline{\mathrm{Explanation}}}$

∴Now, Area of floor

$\sf\red{ ⇒l×b}$

$\sf\red{ ⇒=15×12=180 {m}^{2} }$

∴Area of walls :

$\sf\green{⇛ 2h(l+b)}$

$\sf\green{ ⇛2×2(15+12)}$

$\sf\green{⇛4×27=108{m}^{2} }$

Total area = 108+180

${\boxed{288{m}^{2} }}$

⠀━━━━━━━━━━━━━━━━━━━━━━━━

$\sf\red{Cost\: of \:cementing \: :- }$

$\sf\blue{ ⇛Rs.15 \:per\: square\: meter}$

∴Therefore,

⠀⠀⠀⠀⠀⠀Cost of cementing the floor and wall of pool :

$\sf\blue{ ⇛15×288}$

${\boxed{⇛ Rs.4320}}$