4) A train travelling at 20 m s-1 accelerates at 0.5 m s-2 for 30 s. How far will it travel in this time?
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Answer:
u = 20 m/s
a = 0.5 m/s²
t = 30 sec
From 2nd equation,
s = ut +(1/2) at²
= 20×30 + (1/2)×0.5×(30)²
= 825 m.
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