4. A work of 4900 J is done on load of mass 50 kg to lift it to a certain height. Calculate the
height through which the load is lifted.
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2
Answer:
Since, the object is raised to certain height, the work done is equal to the potential energy stored in the body.
So, W = PE = mgh where m is the mass, g is the acceleration due to gravity and h is the height upto which the object is raised.
Here, 4900 = 50 × 9.8 × h ( g = 9.8m/s²)
\begin{gathered}h \: = \frac{4900}{50 \times 9.8} = \frac{4900}{5 \times 98} \\ \\ h = 10\end{gathered}
h=
50×9.8
4900
=
5×98
4900
h=10
Therefore, the object is raised to a height of 10m.
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Answer:
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Explanation:
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