Math, asked by kaushr2006, 10 months ago

4.A Yacht, 32 3 meters in height, is floating on water. If 1 6 th of its height is under water, then what is the height of the yacht visible above the water.

Answers

Answered by 123duttasudip72
8

Answer:

55/18 or 3 1/18

Step-by-step explanation:

Total height = 3 2/3 = 11/3 (converting mixed fraction to improper fraction)

length under water = 1/6 of total = 1/6 x 11/3 = 11/18

length visible above water = 11/3 - 11/18 ( difference of total with length below water)

66/18 - 11/18 (LCM of denominator to subtract)

55/18 (improper fraction) or 3 1/18 (mixed fraction)

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Answered by adarshdutta50
1

Answer:

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He is totally correct....

Step-by-step explanation:

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