Question

4. ABC is a triangle in which altitudes BE and CF to
sides AC and AB are equal (see Fig. 7.32). Show
that
1) A ABE=AACF
(11) AB =AC, i.e., ABC is an isosceles triangle.
B
Fig. 7.32​

Answer 1

Answer:

given BE=CF , now in triangle ∆ABE and ∆ACF BE =CF (given) , <AEB=<ACF (BE and CF are altitude) ,<A=<A ( common angle), by AAS congruency ∆ABE congruence ∆ACF 2. by CPCT AB=AC