Question

4. ∆ABC-∆PQR, AC = 8cm, PR-4 cm, QR = 6 cm then find BC.​

Answer 1

Given: Δ$ABC$ ~Δ$PQR$

            $AC=8CM\\PR=4CM\\QR=6CM$

To find: $BC$

Step-by-step explanation:

Since the triangles are  similar,

∴ $\frac{AB}{PQ} =\frac{BC}{QR}=\frac{AC}{PR}$

    $\frac{BC}{QR}=\frac{AC}{PR}$

    $\frac{BC}{6}=\frac{8}{4}=2$

$BC=6*2=12cm$