Question

4. AD is a diameter of a circle and AB is a chord. If AD = 34 cm, AB = 30 cm, the distance of AB
from the centre of the circle is
(a) 17 cm (b) 15 cm
(c) 4 cm
(d) 8 cm
​

Answer 1

Answer:

(d) 8 cm

Step-by-step explanation:

Answer 2

Answer:

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Step-by-step explanation:

OX is the perpendicular distance from centre O to the chord AB

∴AX=XB

Now,

AX+XB=AB

⇒2AX=AB

⇒2AX=30

⇒AX=230

⇒AX=15

Again,

AO+OD=AD

⇒2AO=AD

⇒2AO=34

⇒AO=17

△AOX is a right angled triangle

∴AO2=OX2+AX2

⇒172=OX2+152

⇒OX2=172−152

⇒OX2=64

⇒OX=8cm