Question

4. Age of a man is 10 times to His Son. After 4 years.HIS Age becomes 4times to HiS Son. Then find their Present Age a)4,40years B) 2,20 years C)3,30 years d) 2,22 years​

Answer 1

• Let the age of son = x
• Age of man = 10x

$\large\blue{\bf{•\:After\: 4\: years}}$

• Age of man = 10x+4
• age of son = 4(x+4)

${\pink{\bf{4(x+4)=10x+4}}}$

${\pink{\tt{➣ 4x+16 =10x+4}}}$

${\pink{\tt{➣ -4+16= 10x-4x}}}$

${\pink{\tt{➣ 12 = 6x}}}$

$\pink{➣}$${\pink{\tt{\cancel{\frac{12}{6}}}}}$

${\pink{\boxed{\tt{➣ 2}}}}$

${\red{\bf{∴\:Age\: of\: son\: =\: 2}}}$

${\red{\bf{Age\: of\: man\: ➣ \:10x2 =\: 20}}}$

${\bf{\color{springgreen}{\boxed{☑ \:Option \:B \:is \:the \:correct\: answer\: 2,20 \:years}}}}$

${\color{red}▬{\color{navy}▬▬{\color{purple}▬▬{\color{springgreen}▬▬{\color{grey}▬▬{\color{aqua}▬▬{\color{gold}▬▬{\color{red}▬}}}}}}}}$

${\color{brown}●{\color{pink}●{\color{gold}●{\color{red}{\tt Hope\: {\mathfrak{\color{greenyellow}it\: {\bf{\color{springgreen}helps{\color{Ivory}●{\color{lightpink}●{\color{Magenta}●}}}}}}}}}}}}$

${\color{aqua}{\underbrace{\color {lime}{\overbrace{\color{#DA70D6}@ {\color{red}{\bf S{\color{springgreen} N{\color{yellow}E{\color{#00ffff}H{\color{pink}A{\color {purple}S{\color {#a52a2a}H{\color {#A9a9a9} I{\color {gold}S{\color{orange}H}}}}}}}}}}}}}}}}$

Answer 2

Answer:

Step-by-step explanation:

Son=d

father=d*10

after 4 years

son=d+4

father=(d*10)+4

father=