Question

4.An object travels 16 m in 4 sand then another 16 m in 2 s. What is the average speed of the object?
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Answer 1

the average speed is 6 meter per second

Answer 2

Answer:

The average speed of the object is 5.33 m/s.

The average speed of the object is 5.33 m/s.Explanation:

The average speed of the object is 5.33 m/s.Explanation:Velocity V = \bold{=\frac{\text {distance}}{t i m e}}=

The average speed of the object is 5.33 m/s.Explanation:Velocity V = \bold{=\frac{\text {distance}}{t i m e}}= time

The average speed of the object is 5.33 m/s.Explanation:Velocity V = \bold{=\frac{\text {distance}}{t i m e}}= timedistance

The average speed of the object is 5.33 m/s.Explanation:Velocity V = \bold{=\frac{\text {distance}}{t i m e}}= timedistance

The average speed of the object is 5.33 m/s.Explanation:Velocity V = \bold{=\frac{\text {distance}}{t i m e}}= timedistance

The average speed of the object is 5.33 m/s.Explanation:Velocity V = \bold{=\frac{\text {distance}}{t i m e}}= timedistance Distance traveled by an object in part 1, D1 = 16 m

The average speed of the object is 5.33 m/s.Explanation:Velocity V = \bold{=\frac{\text {distance}}{t i m e}}= timedistance Distance traveled by an object in part 1, D1 = 16 mTime taken by an object (in part 1), T1 = 4 seconds

The average speed of the object is 5.33 m/s.Explanation:Velocity V = \bold{=\frac{\text {distance}}{t i m e}}= timedistance Distance traveled by an object in part 1, D1 = 16 mTime taken by an object (in part 1), T1 = 4 secondsDistance traveled by an object in part 2, D2 = 16 m

The average speed of the object is 5.33 m/s.Explanation:Velocity V = \bold{=\frac{\text {distance}}{t i m e}}= timedistance Distance traveled by an object in part 1, D1 = 16 mTime taken by an object (in part 1), T1 = 4 secondsDistance traveled by an object in part 2, D2 = 16 mTime taken by in part 2, T2 = 2 seconds

The average speed of the object is 5.33 m/s.Explanation:Velocity V = \bold{=\frac{\text {distance}}{t i m e}}= timedistance Distance traveled by an object in part 1, D1 = 16 mTime taken by an object (in part 1), T1 = 4 secondsDistance traveled by an object in part 2, D2 = 16 mTime taken by in part 2, T2 = 2 secondsAverage speed of an object =\frac{D 1+D 2}{T 1+T 2}=

The average speed of the object is 5.33 m/s.Explanation:Velocity V = \bold{=\frac{\text {distance}}{t i m e}}= timedistance Distance traveled by an object in part 1, D1 = 16 mTime taken by an object (in part 1), T1 = 4 secondsDistance traveled by an object in part 2, D2 = 16 mTime taken by in part 2, T2 = 2 secondsAverage speed of an object =\frac{D 1+D 2}{T 1+T 2}= T1+T2

The average speed of the object is 5.33 m/s.Explanation:Velocity V = \bold{=\frac{\text {distance}}{t i m e}}= timedistance Distance traveled by an object in part 1, D1 = 16 mTime taken by an object (in part 1), T1 = 4 secondsDistance traveled by an object in part 2, D2 = 16 mTime taken by in part 2, T2 = 2 secondsAverage speed of an object =\frac{D 1+D 2}{T 1+T 2}= T1+T2D1+D2

The average speed of the object is 5.33 m/s.Explanation:Velocity V = \bold{=\frac{\text {distance}}{t i m e}}= timedistance Distance traveled by an object in part 1, D1 = 16 mTime taken by an object (in part 1), T1 = 4 secondsDistance traveled by an object in part 2, D2 = 16 mTime taken by in part 2, T2 = 2 secondsAverage speed of an object =\frac{D 1+D 2}{T 1+T 2}= T1+T2D1+D2

The average speed of the object is 5.33 m/s.Explanation:Velocity V = \bold{=\frac{\text {distance}}{t i m e}}= timedistance Distance traveled by an object in part 1, D1 = 16 mTime taken by an object (in part 1), T1 = 4 secondsDistance traveled by an object in part 2, D2 = 16 mTime taken by in part 2, T2 = 2 secondsAverage speed of an object =\frac{D 1+D 2}{T 1+T 2}= T1+T2D1+D2 = 16 + 16 / 4 + 2 = 5.33 m/s