Question

4. Answer the following questions. Each question carries 2 marks.
(8 marks)
a) Rahul buys 3 types of balls. Type 1 costs 10 each, Type 2 costs 78 each, and
Type 3 costs 25 each. What is the least number balls of each type he should buy so
that he spends an equal amount on each type of ball?​

Answer 1

Answer:

clearly this is a problem of finding LCM.

LCM of 10, 78, and 25

primae factorisation of

10 = 2*5

78 = 2*3*13

25 = 5*5

LCM = 2*3*5*5*13

= 1950

thus, he would buy

1950/10 = 195 balls costing 10 each

1950/78 = 25 balls costing 78 each

1950/25 = 78 balls costing 25 each.

In that way he would spend 1950 in buying each type of balls

His total expenditure would be 1950+1950+1950

= 5850

Answer 2

Answer:

Explain by Explain

LCM =10,78,25

prime factorisation of

10=2*5

78=2*3*13

25=5*5

LCM= 2*3*5*5*13

= 1950

Thus ,he would buy

1950/10=195 balls costing 10 each

1950/78=25 balls costing 78 each

1950/25 = 78 balls costing 25 each

In that way he would spend 1950 in buying each types of balls

His total expenditure would be

1950+1950+1950

= 5850