Question

4. As shown in the diagram, points P and R form a straight line with point charge q. Point P is located 25 cm from q, and point R is located 75 cm from q. Let E p equal the magnitude of the electric field at point P. What is the magnitude of the electric field at point R?

A)Ep/3
B)Ep/9
C)Ep/50
D)Ep/25

Answer 1

Answer:

Hence option Ep/ 9 is the correct answer

Answer 2

The magnitude of the electric field at point R is option B)Ep/9

Explanation:

The computation of the magnitude of the electric field at point R is shown below:

Given that

The Electric field at point P = $E_{p}$

Distance of Q from Point P = 25

Distance of Q from Point R = 75

That means

Distance of Q from Point R = 3 times of Distance of Q from Point P

Electric field is inversely proportional to $r^{2}$

For better understanding

$E_{p} = \frac{k\times\text{Q}}{ r^{2} }$

$E_{r} = \frac{k\times\text{Q}}{(3r)^2}}}$

$E_{r} = \frac{k\times\text{Q}}{{9r^{2} }}$

Therefore

$E_{r} = \frac{E_{p} }{9}$

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