Question

4) At a rate of 10 p.c.p.a., what would be the interest for
one year on Rs.6,000​

Answer 1

$\bf \: \underline{ {Given}} :$ ↴

$\sf \: Principal = Rs. \: 6000$

$\sf \: Rate = 10 \: \%$

$\sf \: Time = 1 \: year$

$\bf \: \underline{To \: find} :$ ↴

$\sf \: We \: have \: to \: find \: the \: simple \: interest.$

$\sf \: As \: we \: know \: that,$

$\underline{ \boxed{ \pink{\sf \: \sf{Simple \: Interest = \dfrac{P \times R \times T}{100}}}}}$

$\sf \: Where,$

$\sf \bigodot \: \longrightarrow \: P = Principal$

$\sf \bigodot \: \longrightarrow \: R = Rate$

$\sf\bigodot \: \longrightarrow \: T = Time$

$\sf \: Putting \: the \: values,$

$\sf \: \sf{Simple \: Interest = \dfrac{6000 \times 10 \times 1}{100}}$

$\sf \: Cancel \: the \: zero,$

$\sf{ \longrightarrow \: \dfrac{60 \!\!\!\not 0 \!\!\!\not 0 \times 10 \times 1}{1 \!\!\!\not 0 \!\!\!\not 0}}$

$\sf \: Simplify \: the \: above \: expression,$

$\sf{ \longrightarrow \: 60 \times 10 \times 1}$

$\sf \: Multiply \: the \: numbers,$

$\sf{ \longrightarrow \: 600}$

$\underline{ \boxed{ \green{\sf \: Hence \: the \: Simple \: Interest = Rs. \: 600}}}$

Answer 2

Simple Interest = Rs. 600

Explanation :

$\boxed{ \bf \dfrac{Principal \times Time \times Rate}{100} }$

Simple Interest :

$\bf \: \dfrac{6000 \times 1 \times10}{100}$

$\bf \: \dfrac{60 \times 1 \times10}{1}$

$\bf \: 60 \times 10 = 600$

$\bf \: Simple \: Interest = Rs. \: 600$