Question

4. b) The mother bear is fed 4 fish for every 2 fish that her cub is fed. How many fish would the cub get if the mother is fed: 20 fishes? *

Answer 1

Step-by-step explanation:

Neutralization Reactions

acid + base → water + salt. ...

HCl(aq) + KOH(aq) → H 2O(ℓ) + KCl(aq) ...

2 HCl(aq) + Mg(OH) 2(aq) → 2 H 2O(ℓ) + MgCl 2(aq) ...

3 HCl(aq) + Fe(OH) 3(s) → 3 H 2O(ℓ) + FeCl 3(aq) ...

HCl(aq) + NaOH(aq) → H 2O(ℓ) + NaCl(aq) ...

H +(aq) + Cl −(aq) + Na +(aq) + OH −(aq) → H 2O(ℓ) + Na +(aq) + Cl −(aq) ...

H +(aq) + OH −(aq) → H 2O(ℓ)