Question

4. By what least number should 4608 be multiplied so that product is a perfect cube? Also find the cube
root of the product so obtained.


please explain ​

Answer 1

Answer:

First we have to prime factorise the given number

4608÷2=2304

2304÷2=1152

1152÷2=576

576÷2=288

288÷2=144

144÷2=72

72÷2=36

36÷2=18

18÷2=9

9÷3=3

3÷3=1

So now we have to group same 3 number (since it is cube)

so (2×2×2)(2×2×2)(2×2×2)(3×3)

since 3 does not have triplets

so we have to multiply the 4608 by3

cube root is 2×2×2×3=24