Math, asked by saroj7sharma, 1 month ago

4(c-a) by (a^2 - b^2+ 12c)​

Answers

Answered by vajmera0
0

Step-by-step explanation:

  • 4xc - 4x a x ( a^2 - b^2 + 12c )
  • 4c - 4a (a^2 - b^2 + 12c )
  • 4c (a^2 - b^2 + 12c) - 4a ( a^2 - b^2 +12c )
  • 4c x 2a^2 - 4c x b^2 + 4a x 12c - 4a x a^2 + 4a x b^2 + 4a x 12c
  • 4a^2c - 4b^2c +48c^2 - 4a^3 + 4ab^2 +48ac
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