Question

4. Calculate the number of moles glucose present in 18gm C6H,206. 12 A​

Answer 1

0.1 moles

Explanation:

Given: mass of Glucose = 18 g

1 mole of glucose = 180 g

18 g of Glucose = 18/180

                           = 0.1 moles of glucose will have mass of 18 g