4 cards are drawn without replacement from pack of cards. what is the probability that they all are of different suit?
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total cards present in pack are 52
and four are drawn from it so = 4 / 52 => 1 / 13
plz mark me brainliest
and four are drawn from it so = 4 / 52 => 1 / 13
plz mark me brainliest
gunjandewani14:
But book answer is 2197/20825
OMEGA = 52 x 51 x 50 x 49
A = 52 x 48 x 44 x 40
P(A) = A/OMEGA = 0.68
A = 52 x 48 x 44 x 40
P(A) = A/OMEGA = 0.68
I don't know that's why I'm asking
No I don't think so
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