4 chairs and 3 tables cost is 210 rupees and cost of 5 chairs and 2tables is 75 rupees find the cost each chair and table separately
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let the cost of 1 chair= x
cost of 1 table=y
2 eqn we get are,
4x+3y=210 -i
5x+2y=75 -ii
multiplying eqn i by 2 and eqn ii by 3
8x+6y= 420
15x+6y=225
subtracting them,
-7x=-195
x= 27.85-cost of 1 chair
substitute value of x in eqn i,
value of y= 32.1- cost of 1 table
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