Question

4. Chord AB || tangent DE.
C is the point of contact.
Prove that AC = BC.​

Answer 1

Answer:

Step-by-step

Answer:

join AC and BC.

OC IS perpendicular to DE.

as AB is parelell to DE, OF is perpendicular to AB⇒AF=BF

In ΔACF ΔBCF

angle F=90

AF=BF

CF=CF

so,ΔACF≅ΔBCF by RHS c.c

by cpct, AC=BC

HP