Question

4 cm 6 cm •C R AABC is right-angled at A. AD is perpendicular to BC, AB=5 cm, BC = 13 cm and AC=12 cm. Find the area of AABC. Also, find the length of AD. 12 cm 5 cm 1 1 B. D 13 cm С APQR is isosceles with PQ = PR = 7.5 cm and QR = 9 cm. The height PS from P to QR, is 6 cm. Find the area of APOR. What will be the height from R to PO i.e. RT?​

Answer 1

Answer:

ΔABC is right angled at A. AD is perpendicular to BC. If AB=5cm, BC=13cm and AC=12cm, find the area of ΔABC. Also, find the length of AD.

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Medium

Solution

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In right angles triangle BAC, AB=5cm and AC=12cm

Area of triangle=

2

1

×base×height=

2

1

×AB×AC

=

2

1

×5×12=30cm

2

Now, in ΔABC,

Area of triangle ABC=

2

1

×BC×AD

⇒30=

2

1

×13×AD

⇒ AD=

13

30×2

=

13

60

cm.