Question

4
Compound contain
69.9% carbon
6.86% Hydrogen and 23.3% oxygen.
Determine
the
Empirical Formula​

Answer 1

Answer:

What is the empirical formula of a compound that contains 69.9% carbon (C), 6.86% hydrogen (H) and 23.3% oxygen (O)?

Explanation:

Molar masses: C = 12.0 g/mol, H = 1.0 g/mol, O = 16.0 g/mol

As no. of moles = mass / molar mass

In the compound, mole ratio C : H : O

= 69.9/12.0 : 6.86/1.0 : 23.3/16.0

= 5.83 : 6.86 : 1.46

= 5.83/1.46 : 6.86/1.46 : 1.46/1.46 ….. divided by the smallest number, 1.46

= 4 : 4.67 : 1

= 12 : 14 : 3

Empirical formula = C₁₂H₁₄O₃

Answer 2

Answer:

The empirical formula of CH20 is C12H14O3