4.
constant acceleration of 2 ms-2 on a straight
A car having initial velocity 15 ms-1 moves with a constant acceleration of straight
road. The displacement of the car in 5th second
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d = vt + 1/2 at^2
= 15(5) + 1/2(2)(5)^2
=75 + 25
= 100
brainer79:
It's wrong. .correct answer is 24m
ya sorry bro..
right method is here
plss send
d = v +(2n-1)t/2. == 15 + (2(5) - 1)2/2. ==. 15+9. == 24
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