Question

4. Construct a rhombus ABCD with AB = 5.3 cm and angle A = 60°. Draw its line (or lines)
of symmetry​

Answer 1

Answer:

Steps to construct:

Step 1 : Draw a line segment AB = 5.3cm

Step 2 : Construct an angle of 90

0

at point A.

Step 3 : With A as centre, radius = 5.3 cm draw an arc on AX. Make the point of intersection as D.

Step 4 : With D as the centre and radius = 5.3 cm draw an arc. Mark that point as C.

Step 5 : With B as centre and same radius, draw another arc, such that it intersects the previous at point C.

Step 6 : Join CD and BC

Step 7 : ABCD is a required rhombus.

The lines of symmetry:

Lines of symmetry in rhombus = 2, i.e. the diagonals of the rhombus.

Step-by-step explanation:

I hope it will help you thanks

good morning

Answer 2

Answer:

• REQUIRED ANSWER :)

Steps to construct :-

1. Draw a line segment AB = 5.3cm
2. Construct an angle of 90° at point A.
3. With A as centre, radius = 5.3 cm draw an arc on AX. Make the point of intersection as D.
4. With D as the centre and radius = 5.3 cm draw an arc. Mark that point as C.
5. With B as centre and same radius, draw another arc, such that it intersects the previous at point C.
6. Join CD and BC
7. ABCD is a required rhombus.

The lines of symmetry:

Lines of symmetry in rhombus = 2, i.e. the diagonals of the rhombus.