4 cos theta -5 sin theta = 0 find sec theta
plzz solve this question step by step fast i will mark you as brainlist
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4cosQ-5sinQ=0
4cosQ=5sinQ
4/5cosQ=sinQ
tanQ=4/5
therefore in a triangle (4)^2+(5)^2=√41(hypotenuse)
therefore cosQ=5/√41.
secQ=1/cosQ
secQ=√41/5
I hope this will help you
I hope this is the correct answer which u wanted
4cosQ=5sinQ
4/5cosQ=sinQ
tanQ=4/5
therefore in a triangle (4)^2+(5)^2=√41(hypotenuse)
therefore cosQ=5/√41.
secQ=1/cosQ
secQ=√41/5
I hope this will help you
I hope this is the correct answer which u wanted
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