4 cubes of sides 4cm are joined end to end. The surface area of the resulting solid is?
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Answered by
10
hey
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length = 4+4+4+4 = 16cm
breadth= 4 cm
height = 4cm
after joining the cubes , it will form cuboid
surface area of cuboid = 2(lb + bh+ lh)
= 2(16*4+4*4+16*4)
= 2(64+16+64)
= 2(144)
= 288 cm ^2
hope helped
______________
_______
length = 4+4+4+4 = 16cm
breadth= 4 cm
height = 4cm
after joining the cubes , it will form cuboid
surface area of cuboid = 2(lb + bh+ lh)
= 2(16*4+4*4+16*4)
= 2(64+16+64)
= 2(144)
= 288 cm ^2
hope helped
______________
trisha10433:
thnx bro
Answered by
11
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4 cubes of side 4 cm are joined end to end. The surface area of the resulting solid is -?
♦ Given side of a cube = 4 cm
• Then,
Length of cube = 4 cm
breadth of cube = 4 cm
height of cube = 4 cm
♦ There are 4 such cubes.
♦ They are joined end to end, i.e., their length are joined. Breadth and height remain the same. Clearly they will form a cuboid.
• Then,
Length of cuboid = sum of lengths of cubes = 4 + 4 + 4 + 4 = 16 cm
Breadth of the cuboid = 4 cm
Height of cuboid = 4 cm
♦ Now,
Surface area of a cuboid = 2 (lb + bh + hl)
♦ Then, Surface area of resulting cuboid,
= 2 (lb + bh + hl)
= 2 [(16 × 4) + (4 × 4) + (4 × 16)]
= 2(64 + 16 + 64)
= 2(144)
= 288 cm².
•°• The surface area of resulting solid (cuboid) is 288 cm².
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