4(d) Draw an equilateral triangle such that i hbar one vertex is on Origin, second is 0nX - alpha and third vertex is in first Quadrant. Find its area
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Step-by-step explanation:
Slope of the line x=3y is 31 which is 30∘ with the positive x-axis.
As it is an equilateral triangle the other vertex must be on x=−3y
Let the side be (x,y). Hence,
x2+y2=a2
4y2=a2
y=±2a.
Similarily, x=±23a
Hence, if the triangle lies in the 1st quadrant and 4th quadrant vertex is (23a,−2a)
If the triangle lies in the 2nd and 3rd quadrant the vertex is
(−23a,−2a
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