Question

plz answer my question
physics ch. force, numericals​

Answer 1

Answer:

2,60,680 N = 2.60680 × $10^{5}$ ≈ 2.61 ×$10^{5}$ (Rounding off 2.60680 to 2.61)

Explanation:

F = ma

Here, m = 13300 kg

Given : Initial Velocity (u) = 0 m/s

          : Final Velocity (v) = 56 m/s

         : Distance (s) = 80 m

Now we need to find acceleration (a) for finding Force, as F = ma

⇒ $v^{2} -u^{2} = 2as$  (Third equation of Motion)

⇒ $56^{2} -0^{2} = 2a(80)$

⇒ 3,136 = 160a

⇒ $\frac{3136}{160}$ = a

⇒ 19.6 = a

Now substitute the value of a in F = ma

⇒ F = 13300 × 19.6

⇒ F = 2,60,680 N

Hope it helps

(Try re-learning the equations of motion and understanding the quantities involved in it. Also in such questions write the given data and the quantity to be found before handed. Trust me it really helps.)

If you have anymore queries feel free to disturb me again.