Question

4.
Equal moles of O2, N2, and He gas are kept in a
closed container at pressure 900 mm of Hg. If half
of the molecules of N, are removed then the
resultant pressure of gases in the container is
(1) 750 mm of Hg (2) 600 mm of Hg
(3) 900 mm of Hg (4) 150 mm of Hg​

Answer 1

Answer:

1) = 750 mmHg

Explanation:

Total pressure exerted by mixture of gases is 900 mmHg.

The moles of all three gases are same so each gas will exert 300 mmHg.

When the half molecules of nitrogen are removed than its pressure reduced to 150 mmHg.

300/2 = 150mmHg

or

900 mmHg - 150 mmHg = 750 mmHg

Answer 2

Hola mate

Here is your answer -

answer is 750

Because remove of half molecules of N the final mole of nitrogen is half

P1/P2 = N1/N2

P2 = 750mm of hg