4. Factorize aº +bº and prove that its value is zero if a4 +64 = a_b2.
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Answer:
8(a−2b)
2
−2a+4b−1
⇒8(a−b)
2
−2(a−2b)−1
⇒ Take a−2b=x
∴8x
2
−2x−1
⇒8x
2
−4x+2x−1
⇒4x(2x−1)+1(2x−1)
⇒(4x+1)(2x−1)
∴(4(a−2b)+1)(2(a−2b)−1)
⇒(4a−8b+1)(2a−4b−1).
Step-by-step explanation:
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