Question

4. Find:
(i) The 10th term of the AP 63, 58, 53, 48, ...
11th term of the AP 9,5, 1, -3, ...
.​

Answer 1

Answer:

(i) 18

(ii) -31

Step-by-step explanation:

(i)

nth term of an AP = a+(n-1)d

a= first term of an AP

n= number of terms

d=common difference

In the question,

a=63; n=10; d=-5

By substituting the values, you get the answer as 18

(ii)

Use the same formula,

a=9; n=11; d=-4

Answer 2

Step-by-step explanation:

i) for the AP:- 63, 58, 53, 48,...

a= 63, d= -5, n= 10 and we have to find a10

we know that

${a}^{n} = a + (n - 1) \times d$

now putting the values

a10= 63+(10-1)×(-5)

=>63-45

=>18 (ans)

so the 10th term of the AP is 18.

ii) for the AP:- 9, 5, 1, -3...

a=9, d= -4, n=11 and we have to find a11

putting the values

a11=9+(11-1)×(-4)

=>9-40

=>-31 (ans)

so the 11th term of the AP is -31.