Question

4. Find the 12th term of the A.P.

Answer 1

Hi ,

Given A.P is

√2 , 3√2 , 5√2 , ...

first term = a = √2

common difference ( d ) = a2 - a1

d = 3√2 - √2

d = 2√2

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We know that ,

If first term , common difference of the A.P

be a and d respectively ,

nth term = an = a + ( n - 1 )d

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Here ,

n = 12 , a = √2 , d = 2√2

a12 = a + 11d

= √2 + 11 × 2√2

= √2 + 22√2

= 23√2

Therefore ,

12th term of given A.P = a12 = 23√2

I hope this helps you.

: )