Question

4. Find the 13th and 16th terms of the sequence defined by

Answer 1

HELLO DEAR,

here, already defined for n is even or n is odd.

Fore even,

n = 16,

$\bold{b_n = n^2}\\ \\ \bold{b_{16} = 16^2}\\ \\ \bold{b_{16} = 256}$

For odd,

n = 13,

$\bold{b_n = n(n + 2)}\\ \\ \bold{b_{13} = 13(13 + 2)}\\ \\ \bold{b_{13 }= 195}$

I HOPE ITS HELP YOU DEAR,

THANKS

Answer 2

Solution :

It is given that $b_{n} = \left \{ {{n^{2} }  \atop {n(n+2)}} \right.$

Now ,

1 ) if n= 13 ( odd )

$b_{n} = n(n+2)$

$b_{13} = 13( 13+2)$

= 13 × 15

= 195

2 ) If n= 16 ( even ) ,

$b_{n} = n^{2}$

$b_{16} = 16^{2}$

= 256

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