Question

4. find the 9th term of the arithmetic sequence with a1=10 and d=1/2

Answer 1

Given:

a1 = 10

d = 1 / 2

To find:

a9

Solution:

an = a1 + ( n - 1 ) * d

Here,

a9 = 10 + 9 * 1 / 2

a9 = 10 + 4

Hence, a9 = 14

Answer 2

Given:

$The \quad first \quad term \quad a_{1} = 10$

The common difference $d= \frac {1}{2}$

To find:

The “9th term” of the arithmetic sequence

Answer:

Given that

First term of the sequence $a_{1}=10$ and

Common difference of the terms is $d= \frac {1}{2}$

We need to find the “9th term” of the arithmetic sequence

i.e. $a_{9}=?$

Here, n=9

Formula is

$a_{n}= a_{1}+ (n-1) \times d$

$a_{9} = 10 + (9-1) \times \frac {1}{2}$

$a_{9} =10 + 8 \times \frac {1}{2}$

$a_{9} =10+4$

$a_{9} = 14$

The “9th term” of the given sequence is 14.

The series is given by 10, 10.5, 11, 11.5, 12, 12.5, 13, 13.5, and 14.