Question

4 Find the area of a square whose perimeter is
equal to the perimeter of a regular octagon of
it can have.
side 3 cm.​

Answer 1

Answer:

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Step-by-step explanation:

Solution

A=2(1+2)a2=2·(1+2)·32≈43.45584

Answer 2

$\huge\underbrace{\mathfrak{SoluTion:}}$

Given,

Side of Regular Octagon = 3cm

$\boxed{\sf{Perimeter\;of\; Regular\;Octagon = 8(Side)}}$

$→\;{\tt{8×3}}$

$◕➜\;{\tt{24cm}}$

Perimeter of Square ☞ $\fbox\red{24cm}$

As, Perimeter of Square = Perimeter of Regular Octagon

Perimeter of Square = 24cm

Let's, Side of Square be 's'

$\boxed{\sf{Perimeter\;of\; Square = 4(side)}}$

$→\;{\tt{4s = 24}}$

$→\;\Large{\tt{s = {\cancel{\frac{24}{4}}}}}$

$→\;{\tt{s = 6cm}}$

Side of Square = $\fbox\pink{6cm}$

$\boxed{\sf{Area\;of\; Square = (Side)²}}$

$→\;{\tt{6²}}$

$→\;{\tt{36cm²}}$

Area of Square ☞ $\Large\fbox\green{36cm²}$

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