Question

4- Find the area of a triangle two sides of which are 18cm and 10cm and the perimeter is
42cm​

Answer 1

Refer to the attachment

Answer 2

Answer:

Step-by-step explanation:

given, one side=10cm , another side=18cm and the perimeter =42cm

perimeter of triangle =sum of all sides of triangle. So, let the third side be x

        10+18+x=42

          28+x=42

                x=42-28

                 x=14

therefore,third side =14cm.

area of triangle =1/2×breadth ×height

we know that,

the hypotenous is the largest side of the triangle,therefore 18cm is the hypotenous of the given triangle. So the breadth and height of the triangle are 10 cm and 14 cm. [as per the question, it is not given specifically that so and so side is breadth or height of the triangle,so we can consider any of these two sides as breadth or height]

are of the given triangle =1/2×10×14

                                        = 5×14

                                        =70cm^2

therefore the area of the triangle is 70cm^2.

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