4. Find the area of shaded and unshaded portions.
22 m,3 m,18m,3m
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Answer:
Length = 22 m
Breadth = 3 m
Area = lb = 22 × 3 = 66sq.m
Length = 18 m
Breadth = 3 m
Area = lb = 18 × 3 = 54sq.m
Side = 3 m
Area = S × S = 3 × 3 = 9sq.m
(66 - 9) sq.m = 57 sq.m
(54 - 9) sq.m = 45 sq.m
Total area the shaded part covers = 57 sq.m + 9 sq.m + 45 sq.m = 111 sq.m
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Step-by-step explanation:
area of shaded region = 22 ×3 + 18×3 +3×3
= 66 + 54 + 9
129m^2
area of whole fig = 22 ×18 = 396m^2
area of unshaded region = 396m^2-129m^2
267m^2 ans..
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