Question

4. Find the average of the smallest and the greatest three-digit numbers that are divisible by 13. (1) 546 (2) 1092 (3) 104 (4) 988 1 5 Rahul caorod​

Answer 1

Answer:

1) 546

Step-by-step explanation:

Consider a number 100 divided by 13 and remainder is 9

so 100+(13-9)=104 is smallest number required

now consider a number 999 divided by 13 we get remainder 11

so 999-11= 988 is largest number required

∴average = (   104+988)/2 =546