Question

4) Find the energy of radiation whose
wave length is 3000A
​

Answer 1

Answer:

6.63*10( 19 Ki power )jule

Answer 2

Answer:

6.626*10^-19 J

Explanation:

We know that 1A°=10^-10m

and

E=hc/ lambda

so, E= 6.626*10^-34 *3*10^8/3000 * 10^-10

E= 6.626*10^-19