Question

4. Find the initial velocity of a train, which is stopped in 25 seconds. The retardation produced in the train is 1.5 m/s2.



I tried but I can’t get the answer.

Answer 1

Answer:

37.5$ms^{-1}$

Explanation:

v = 0

t = 25

a = -1.5

v = u + at

0 = u + (25 x -1.5)

0 = u - 37.5

u = 37.5$ms^{-1}$

Answer 2

Answer:

INITIAL VELOCITY (U)=x

FINAL VELOCITY(V)=25

RETARDATION=1.5

R=$\frac{U-V}{T}$

1.5=$\frac{x-25}{1.5}$

ANS.-11.11

I HAVE TAKEN UPTO TWO DECIMAL PLACES.

Explanation:

MARK BRAINLIEST!