Question

4) Find the number of terms in the AP 3, 6, 9, 12.111​

Answer 1

Answer:-t1=3,t2=6,t3=9,t4=12

d=t2-t1=6-3=3

t3-t2=9-6=3

t4-t3=12-9=3

Here,a=t1=3

tn=a+(n-1)d

t111 =3+(111-1)3

=3+110×3

=3+330

t111 =333