Question

4. Find the ratio in which the line segment joining
the points p (3,-6) and Q (5,13) is divided
by the x axis​

Answer 1

Answer:

$\pink{\huge{\underline{\underline{❤Answer❤}}}}$

By midpoint theorem:

x=3+5/2=4. ,y=-6+13/2=7/2.....(3)

By section formula :

$x = \frac{mx1 + nx2}{m + n}$

$= y = \frac{my1 + ny2}{m + n}$

Put the following point in the formula :

$x = \frac{m3 + n5}{m + n}$

$xm + xn = 3m + 5n............(1)$

$y = \frac{ - 6m + 13n}{m + n}$

$ym + yn = - 6m + 13n.........(2)$

$xm + xn - 3m - 5n = 0$

$m(x - 3) + n(x - 5) = 0$

$x = 3 \: and \: x = 5$

solve more u get urs answer perfectly

now put the value of eqn (3)

4m+4n=3m+5n

4m+4n-3m-5n=0

m-n=0............(4)

7/2m+7/2n=-6m+13n

7m+7n=-12m+26n

7m+7n+12m-26n=0

19m-19n=0

m-n=0..........(5)

Now solve the linear equation of eqn (4) and (5)

m-n=0

m-n=0

m=0

n=0 OK friend this is urs answer