Question

4. Find the side and perimeter of a square whose area is:
(i) 121 cm²
(ii) 158.76 cm²
(iii) 4 33/64m²


Gift: Who will give all the ans of the above questions I will thank their 5 questionsbut the ans should also be crrt

warning : Don't give unnecessary ans....​

Answer 1

Step-by-step explanation:

(i)Area=121cm²

Area=L²=121cm²

L=

$\sqrt{121{cm}^{2} }$

L=11cm=Side

Perimeter=4L=4*11=44cm

(ii)Area=158.76cm²

Area=L²=158.76cm²

L=12.6cm

Perimeter=4L=4*12.6=50.4cm

(iii)Area=289/64

Area=L²=289/64cm²

L=2.1255cm

Perimeter=4L=4*2.125=8.5cm

Answer 2

$\sf{\red{\underline{\red{\huge{Solutions}}}}}$

(i) $\sf{\huge{\star}}$ Given:-

Area of the square :- 121 cm²

$\sf{\huge{\star}}$ To Find:-

• Side of the square
• Perimeter of the square

$\sf{\huge{\star}}$ Solution:-

We know,

Area of square = (side)²

Therefore

= $\sf{121 = (side)^2}$

$\sf{\implies side = \sqrt{121}}$

$\sf{\implies Side = 11\:cm}$

Therefore the side of the square is 11 cm

Now,

Perimeter of the square = $\sf{4\times side}$

= $\sf{Perimeter = 4\times 11}$

= $\sf{Perimeter = 44\:cm}$

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(ii)$\sf{\huge{\star}}$ Given:-

Area of the square = 158.76 cm²

$\sf{\huge{\star}}$ To Find:-

• Side of the square
• Perimeter of the square

$\sf{\huge{\star}}$ Solution:-

We know,

Area of square = (side)²

Therefore,

= $\sf{158.76 = (side)^2}$

$\sf{\implies side = \sqrt{158.76}}$

$\sf{\implies Side = 12.6\:cm}$

Therefore Side of the square is 12.6 cm

Now,

Perimeter of square = $\sf{4\times side}$

= $\sf{Perimeter = 4\times 12.6}$

= $\sf{Perimeter = 50.4\:cm}$

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(iii) $\sf{\huge{\star}}$ Given:-

Area of the square = $\sf{4\dfrac{33}{64} = \dfrac{289}{64}}$ m²

$\sf{\huge{\star}}$ To Find:-

• Side of the square
• Perimeter of the square

$\sf{\huge{\star}}$ Solution:-

We know,

Area of Square = (side)²

Therefore,

= $\sf{\dfrac{289}{64} = (side)^2}$

$\sf{\implies side =\sqrt{\dfrac{289}{64}}}$

$\sf{\implies Side = \dfrac{17}{8}}$

Therefore the side of the square is $\sf{\bold{\dfrac{17}{8}}}$ m.

Now,

Perimeter of the square = $\sf{4\times Side}$

= $\sf{Perimeter = 4\times \dfrac{17}{8}}$

= $\sf{Perimeter = \not{4} \times \dfrac{17}{\not{8}}}$

= $\sf{Perimeter = \dfrac{17}{2}}$

$\sf{\implies Perimeter = 8.5\:m}$

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Formulas Used:-

• Area of square = (side)² sq.units
• Perimeter of square = 4×side units

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