Question

4. Find the simple interest when

P = 5,500
R = 3-% p.a.
4.
interest when

T = 4 years​

Answer 1

Given :-

• Principle = Rs.5500

• Rate of interest = 3%

• Time = 4 years

To find :-

• Simple Interest

Solution :-

As we know that

→ Simple interest = P × R × T/100

Where " P " is Principle, " R " is rate of interest and " T " is time.

According to the given condition

→ Simple interest = P × R × T/100

→ Simple interest = 5500 × 3 × 4/100

→ Simple interest = 55 × 3 × 4

→ Simple interest = 55 × 12

→ Simple interest = Rs. 660

Hence,

• Simple Interest is Rs.660

Answer 2

Answer:

$\frak {\pink{Given}}\begin{cases} \sf{\green{Principal=Rs.5,500}}\\ \sf{\blue{Time=4\:Years}}\\ \sf{\orange{Rate=3\%}}\\ \sf{\red{Simple \: Intrest=?}}\end{cases}$

☯ $\underline{\boldsymbol{According\: to \:the\: Question\:now :}}$

$:\implies \sf Simple \: Intrest = \dfrac{Principal \times Rate \times Time}{100}$

$:\implies \sf Simple \: Intrest = \dfrac{55 \cancel{00 }\times 3 \times 4}{1 \cancel{00}}$

$:\implies \sf Simple \: Intrest = 55 \times 3 \times 4$

$:\implies \underline{ \boxed{\textsf{ \textbf{ Simple Intrest = Rs. 660 }} }}$

$\therefore\underline{\textsf{ The Simple Intrest is \textbf{Rs. 660}}}$

_______________________

$\boxed{\underline{\underline{\bigstar\:\bf\:Extra\:Shots\:\bigstar}}}$

$\frak{ 1) \: Profit = SP - CP }$

$\frak {2) \: Loss = CP - SP }$

$\frak {3) \: Profit\% = (Profit \:in \:Rs.)*100/CP}$

$\frak {4) \: Loss\% = (Loss \:in \:Rs.)*100/CP}$

$\frak {5) \: SP = CP*(100+P\%)/100}$

$\frak {6) \: SP = CP*(100-L\%)/100}$

$\frak {7) \: CP = SP*100/(100+P\%) }$

$\frak {8) \: CP = SP*100/(100-L\%)}$

$\frak {9) \: Discount =MP - SP}$

$\frak {10) \: Discount\%=(Discount \:in \:Rs.)*100/MP}$

$\frak{ 11) \: MP = SP*100/(100-D\%)}$