Question

4. Find the smallest number which when reduced by 4 is divisible by 35,15 and 13.​

Answer 1

Answer:

1

Step-by-step explanation:

35-4 = 31

15-4 = 11

13-4 = 9

Answer 2

Answer:

The smallest number = LCM of 35,15,13

35 = 5×7

15 = 3× 5

13 = 1× 13

LCM = 5×7×3×13

= 1365

Therefore, the required number = 1365 + 4

= 1369.

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