Question

4. Find the total distance covered by a car in 20
minutes that moves with a uniform speed of 50
km/h for the first 10 minutes and then with a
speed of 60 km/h for the next 10 minutes​

Answer 1

Answer:

We are given that the car has been traveling for about 20 minutes approximately in which the first 10 minutes where driven with different speed by the next 10 minutes with different speed .  

Latest first calculate the distance traveled in the first 10 minutes:-

D 1 = s \times t = speed is 50 km per hour and time is 10 minutes changing time into hour \frac{10}{60} = \frac{1}{6} hr ⇒ 50\times \frac{1}{6} = \frac{50}{6}km

D 2= s \times t =Speed is 60 km per hour and time is 10 minutes again which equals \frac{1}{6} hr

D 2 = 60 \times \frac{1}{6} = 10 km

Adding the two distances to find the total distance = \frac{50}{6} +10 = \frac{110}{6} = \frac{55}{3} km.

Find the total distance covered by a car in 20 minutes that moves with a non uniform speed of 50 kilometre for the first 10 minutes

PLZ MARK AS BRIANLIEST,FLW ME AND THX FOR THE SUPERB QUESTION

Answer 2

Explanation:

The total distance covered by the car is \frac{55}{3}

3

55

Explanation:

We are given that the car has been traveling for about 20 minutes approximately in which the first 10 minutes where driven with different speed by the next 10 minutes with different speed .

Latest first calculate the distance traveled in the first 10 minutes:-

D 1 = s \times× t = speed is 50 km per hour and time is 10 minutes changing time into hour \frac{10}{60} = \frac{1}{6}

60

10

=

6

1

hr ⇒ 50\times \frac{1}{6}×

6

1

= \frac{50}{6}

6

50

km

D 2= s \times× t =Speed is 60 km per hour and time is 10 minutes again which equals \frac{1}{6}

6

1

hr

D 2 = 60 \times \frac{1}{6}60×

6

1

= 10 km

Adding the two distances to find the total distance = \frac{50}{6} +10 = \frac{110}{6} = \frac{55}{3}

6

50

+10=

6

110

=

3

55

km.